Mathematics, 12.06.2020 16:57 zoeyjorschumb17
Jim’s work evaluating 2 (three-fifths) cubed is shown below.
2 (three-fifths) cubed = 2 (StartFraction 3 cubed Over 5 EndFraction) = 2 (StartFraction 3 times 3 times 3 Over 5 EndFraction) = 2 (StartFraction 27 Over 5 EndFraction) = StartFraction 54 Over 5 EndFraction
Which statement best describe Jim’s first error?
He did not multiply Three-fifths by 2 before applying the power.
He did not apply the power to the denominator of Three-fifths.
He did not evaluate 33 correctly.
He did not multiply StartFraction 27 Over 5 EndFraction by 2 correctly.
Answers: 3
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Jim’s work evaluating 2 (three-fifths) cubed is shown below.
2 (three-fifths) cubed = 2 (StartFract...
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