An insurance company checks police records on 582 accidents selected at random and notes that teenagers were at the wheel 15.6% of the time. The standard deviation is 1.2%. Determine the confidence interval that is likely to contain the percent of all teenagers at the wheel when an accident occurred.

At 95% confidence level, the confidence interval that is likely to contain the percent, , of all teenagers at the wheel when an accident occurred is given as follows;

12.7% < < 18.6%

Step-by-step explanation:

The parameters given are as follows;

Sample size, n = 582

Proportion of accidents where teenagers are at the wheel, = 15.6%

x = 0.156*582 ≈ 91

The formula for the confidence interval is as follows;

Where:

z = z value at the confidence level

We therefore have;

At a confidence level of 95%, z = 1.96

The confidence interval at 95% confidence level is therefore;

12.7% < < 18.6%.

the cat is blue because the probability of extension towards the prefix of the diameter of the circle could only mathematically equal to the sum of the roots of the carrots from   your garden.

step-by-step explanation:

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.