The sum of three numbers is 16. The sum of twice the first number, 5 times the second number, and 6 times the third number is 85. The difference between 4 times the first number and the second number is negative 3. Find the three numbers.

Step-by-step explanation:

x, y, z   -  numbers to find

The difference between 4 times the first number and the second number is negative 3:

4x - y = -3

  - y = -3 - 4x

    y = 3 + 4x

The sum of three numbers is 16:

x + y + z = 16

x + 4x + 3 + z = 16

 5x + z = 13

  z = 13 - 5x

The sum of twice the first number, 5 times the second number, and 6 times the third number is 85:

2x + 5y + 6z = 85

2x + 5(3 + 4x) + 6(13-5x) = 85

2x + 15 + 20x + 78 - 30x = 85

      -8x + 93 = 85

        -8x = -8

          x = 1

y = 3 + 4•1 = 7

z = 13 - 5•1 = 8

Veryfying:

1 + 7 + 8 = 16

2•1 + 5•7 + 6•8 = 2 + 35 + 48 = 85

you probably already have the answer but anyways it's b. 15.0

step-by-step explanation: