Mathematics, 26.06.2020 15:01 ian2006huang

Marie and Jorge are both trying to lose weight. After 3 months they compared their weight loss. Marie's weight went from 175 to 150. Jorge's weight went from 190 to 180. Which statements are true regarding their weight loss? Select three options. Jorge's weight change was approximately 5%. Marie's weight change was approximately 14%. Marie had the greater percent change. Jorge had the greater percent change. Marie's weight change was approximately 1.4%.

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Answer from: dixonkaleo9

The accurate statements are:

Jorge's weight change was approximately 5%.

Marie's weight change was approximately 14%

. Marie had the greater percent change.

percentage decrease in each person's weight has to be determined:

Percentage decrease =[ (new weight / old weight) -1 ] x 100

The percentage decrease in Marie's weight = (150 / 175) - 1 = 14%

The percentage decrease in Jorge's weight = (180 / 190) - 1 = 5%

To learn more about percentages, please check: link

Answer from: hamie5124

The answer is given below

Step-by-step explanation:

Marie's former weight = 175

New weight = 150

Difference = 175 - 150 = 25

Percentage change = 25/175 × 100

= 1/7 × 100

= 14.2%

Jorge's former weight = 190

Jorge's new weight = 180

Difference = 190 - 180 = 10

Percentage change = 10/190 × 100

= 5.26%

From the above solving, the following are right

• Jorge's weight change was approximately 5%.

• Marie's weight change was approximately 14%

• Marie had the greater percent change.

Answer from: Quest

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12

Answer from: Quest

-6 is the correct option from the above given options

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