Weekly demand for a product is normally distributed with a mean and standard deviation of 3,211 and 484 units, respectively. What is the probability that weekly demand exceeds 4,044

The probability it is greater than or equal to 0.95 and less than or equal to 0.96

Step-by-step explanation:

In order to calculate the probability that weekly demand exceeds 4,044 we would have to calculate the z value as follows:

Z= (X-mean)/standard deviation

Z= (4044 - 3211)/484

Z=1.721

So, looking for standard normal distribution table 1.7 from row, we get values from 0.9554 till 0.9633, for column 0.02 it is 0.9573

Therefore, the probability it is greater than or equal to 0.95 and less than or equal to 0.96

answer

false

explanation

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geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584