Assume that two marbles are drawn without replacement from a box with 1 blue, 3 white, 2 green, and 2 red marbles. Find the probability of the indicated result. 16) The second marble is blue, given that the first marble is white

second marble is blue and  first marble is white is  

Step-by-step explanation:

given data

two marbles

box = 1 blue, 3 white, 2 green, and 2 red marbles

solution

we get here second marble is blue and given that the first marble is white

= P(3c1 × 1c1) ÷ P(3c1 × 7c1)          ................................................1

= 1c1 ÷ 7c1

= 1 ÷ 7

so second marble is blue and  first marble is white is  

i think is 3 and 6. this took me 10 min to think.hope to and hope that my answer is brainliest.(follow me )

attachment?

step-by-step explanation: