In a random sample, 10 students were asked to compute the distance they travel one way to school to the nearest tenth of a mile. Compute the sample mean, standard mean, standard deviation and variance of the data:1.1 5.2 3.6 5.0 4.8 1.8 2.2 5.2 1.5 0.8 Mean = ???Variance = ???Standard Deviation= ???

Mean = 3.12, Variance = 3.324, Standard deviation = 1.8232

Step-by-step explanation:

Total number of students = 10 students.

Given data, 1.1, 5.2, 3.6, 5.0, 4.8, 1.8, 2.2, 5.2, 1.5, 0.8

To find the mean, at first we have to take the sum of all given data and then divide with the number of students.

Let the data is X, = 1.1, + 5.2, + 3.6, + 5.0, + 4.8, + 1.8, + 2.2, + 5.2, + 1.5, + 0.8 = 31.2

Mean = 31.2 / 10 = 3.12

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation:

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841