An apartment building contains 100 units. The one-bedroom units rent for $495 per month and the two bedroom units rent for $600 per month. When all are rented out, the total monthly rent paid by the tenants is $55,275.How many two-bedroom apartments are there A.45
B.55
C.50
D.66

We have two equations

One to for the total number of units, to distinct them from 1 bedroom units or 2 bedroom units

x- one bedroom units
y- two bedroom units

x+y= 100

495x+600y= 55,275

We can try to plug in these values for y since it’s asks “how many two bedroom apartments are there” and see if it works out

495x+600(45)= 55,275

495x+27000=55275
-27000 -27000

495x= 28275
/495 /495

x=57.12

There can’t be 57.12 units so A is wrong

495x+600(55)= 55,275

495x+ 33000= 55275
-33000 -33000
495x =22275
/495 /495

x=45
This could work so B is the answer , you could go ahead and try C and B but most likely the answer is B

29. because you will divide each number of months by 12 to find the number of years. which would mean, 5, 12.5, 16, 45, 50, 72.5. which is crazy. anyhow, i think you find the median in the middle. and yea hope your test goes good

Hello!

the answer is:

the correct option:

b.

why?

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!