Here is a circle, centre O, and the tangent to the circle at the point (8, 15) on the circle.
x
P (8, 15)
-17
O
17
Find an equation of the tangent at the point P.
Give your answer in the form y = ax + b where a and b are both
fractions with denominator 15.

Solution,

The equation of tangent to a circle with radius 'r' is given by:

x • x1 + y• y1= r^2

where (X1,y1) are point of intersection.

Therefore, the equation becomes:

8x+15y= (17)^2

8x+15y= 289

15y = -8x+289

y= -8/15 x +289/15

Hope this helps..

Good luck on your assignment..

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25