How many complex and real roots are in the problem (x+10)^9.

9 roots

Step-by-step explanation:

(x+10)^9 = 0

If you would multiply it out, the highest power is x^9 so the equation has 9 roots

Solving (x+10)^9 =0

Taking the 9th root of each sdie

x+10 = 0

x = -10

The root is -10 with multiplicity of 9

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.

answer: the angel abc is 30°,and the abc is a triangle where the angel bac is 90°

so ac is the half of 24=12ft,and from the pythagorean theorem we find ba

ba=√bc^2-ac^2=√576-144=√432=12√3ft

so bac is 12+12√3=12(1+√3)ft