The art club is planning a meeting. They are planning to serve cookies and brownie bites and want to have one dessert per person. They expect an attendance of a total of 75 people. Cupcakes (c), come in packs of 6 each, and the brownie bites (b) come in packages of 15. (here is the equation > 6c+15b=75). Question #1) If the treasurer buys 1 package of brownie bites, how many packages of cupcakes are needed according to this equation? Question #2) If the treasurer buys 7 packages of brownie bites, how many packages of cupcakes are needed according to this equation?

see explanation

Step-by-step explanation:

1) 6c + 15(1) = 75

6c = 60

c = 10 packs of cupcakes

2) 6c + 15(7) = 75

6c + 105 = 75

6c = -30

c = -5, since he bought more brownies than needed, he does not need to buy any cupcakes.

6c+15b=75

1)If the treasurer buys 1 package of brownie bites

6(1)+15b=75

15b=75-6

b=69/15=4.6 ( means the treasure needs to buy 5 packages).

2): If the treasurer buys 7 packages of brownie bites,

6c+15(7)=75

6c+105=75

c=-30/6=-5( you can not buy negative amount)

the treasure does not need to buy, because brownies are enough and more.

the results from a pre-test for students for the year 2000 and the year 2010 are illustrated in the box plot. what do these results tell us about how students performed on the 29 question pre-test for the two years?

if we compare only the lowest and highest scores between the two years, we might conclude that the students in 2010 did better than the students in 2010. this conclusion seems to follow since the lowest score of 8 in 2010 is greater in value than the lowest score of 6 in 2000. also, the highest score of 28 in 2010 is greater in value than the highest score of 27 in 2000.

but the box portion of the illustration gives us more detailed information. the middle bar in each box shows us that the median score of 20 in 2000 is greater in value than the median score of 17 in 2010. further, we note that the box and whiskers divide the illustration into four pieces. each of these four pieces represents the same portion of students. so, the upper half of the students in 2000 scored in the same score range as the upper one-fourth of the students in 2010, see the illustration at a score of 20.

by considering the upper one-fourth, upper half, and upper three-fourths instead of just the lowest and highest scores, we would conclude that the students as a whole did much better in 2000 than in 2010. we would conclude that as a whole the students in 2010 are less prepared than the students in 2000.

in this section, we discuss box-and-whisker plots and the five key values used in constructing a box-and-whisker plot. the key values are called a five-number summary, which consists of the minimum, first quartile, median, third quartile, and maximum.

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204