A piece of land ABCD is in the shape of a trapezium as shown in the diagram. AB = 40 m, BC = 39 m,
AD = 30 m, and <ABC = <BAD = 90°. Find
(a) the length of the side CD,
(b) angle BCD,
(c) the area of the land.

a) CD = 41 m

b) 77.32°

c) 1380 square metres

Step-by-step explanation:

We can divide the trapezium as shown in the diagram below.

a) To find CD, we use Pythagoras Rule:

b) To find <BCD, we use trigonometric function SOHCAHTOA:

sin(BCD) = opp / hyp

sin(BCD) = 40 / 41

sin(BCD) = 0.9756

=> <BCD = 77.32°

c) The area of a trapezium is given as:

A = 1/2 (a + b) * h

where h = height = 40 m

a = top length = 30 m

b = bottom length = 39 m

A = 1/2 * (30 + 39) * 40

A = 1/2 * 69 * 40

A = 1380 square metres

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

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answer: d.) the total number of protons and neutrons is 15

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