Approximate the change in the volume of a sphere when its radius changes from r = 40 ft to r equals 40.05 ft (Upper V (r )equals four thirds pi r cubed ). When r changes from 40 ft to 40.05 ft, Upper DeltaValmost equals nothing ftcubed.

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

Step-by-step explanation:

The volume of the sphere (), measured in cubic feet, is represented by the following formula:

Where is the radius of the sphere, measured in feet.

The change in volume is obtained by means of definition of total difference:

The derivative of the volume as a function of radius is:

Then, the change in volume is expanded:

If and , the change in the volume of the sphere is approximately:

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

i dont know and i dont care for math bc it is a stupied subject

step-by-step explanation:

so a parallelogram is just like a square base times height. multiply 40 and 39 to get 1560 inches.

a triangle is base times height divided by two. so multiply 7.9 and 5 and then divide it by 2 to get 19.75inches.

the kite can be split into two separate triangles and added together to get the total area. 30 x 4 /2 which equals 60. make sure to double it for the two triangles making 120.