lands on a field. The height of the ball, in meters, is modeled by the function shown in the graph. What's the average rate of change of the height of the ball from the point when John throws it to its maximum height? Question 10 options: A) 2 meters per second B) –1∕2 meters per second C) –2 meters per second D) 1∕2 meters per second

  A) 2 m/s

Step-by-step explanation:

The ball increases from its thrown height of 3 meters to its maximum height of 7 meters in 2 seconds. That's an average rate of increase of ...

  (4 m)/(2 s) = 2 m/s

The average rate of change of height is 2 meters per second.

 2m/sec

Step-by-step explanation:  From the graph we see that the ball went from 3 meters to 7 meters, a difference of 4m.  It took 2 seconds to reach that height.

The average is found by dividing 4m/2sec

The result is 4m/sec

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.