How to use absolute value to calculate distance in units

i believe that is true.

step-by-step explanation:

hope my answer has you if not i'm sorry.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

its c or d   take a lucky guess my dude

a. is correct