The volume of a spherical cancerous tumor is given by the following equation. V(r) =(4/3)pi r^3 If the radius of a tumor is estimated at 1.4 cm, with a maximum error in measurement of 0.005 cm, determine the error that might occur when the volume of the tumor is calculated:.

The error that might occur is

Step-by-step explanation:

Given

Required

Determine the error that might occur in the volume of the tumor

Given that there's an error in measurement, this question will be solved using the concept of differentiation;

First, we'll rewrite the given parameters in differentiation notations;

--- Radius

--- Change in measurement

--- Volume as a function of radius

The relationship between the above parameters is as follows;

This can be rewritten as

Substitute for

Multiply both sides by dr

Differentiate

Substitute the values of r, dr and take as 3.142

(Approximated)

Hence, the error that might occur is ±0.123

dont think so

step-by-step explanation: