Hi how to solve this pythagoras theorem

The perimeter of the triangle is 40.

Step-by-step explanation:

Pythagorean Theorem:  If x and y are the leg lengths of a right triangle, then r = √(x^2 + y^2) is the length of the hypotenuse.  Alternatively, x^2 + y^2 = r^2.

The side lengths 2x, 4x - 1 and 4x + 1 are already arranged in ascending order.  Thus, (2x^)2 + (4x - 1)^2 = (4x + 1).    

Performing the indicated operations, we get:

         4x^2 + 16x^2 - 8x + 1 = 16x^2 + 8x + 1.  Simplify this first by combining like terms:

         20x^2 - 16x = 16x^2, or

         4x^2 - 16x = 0, or

          4x(x - 4) = 0.  Thus, x = 0 (which makes no sense here) or x = 4.  

The perimeter of the rectangle is the sum of the three sides 2x, 4x - 1 and 4x + 1.  Substituting 4 for x, we get

P = 8 + 16 - 1 + 16 + 1, or 40.

The perimeter of the triangle is 40.                        

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