Can someone please help me

Problem 6, part c)

The tickmarks indicate the sides are the same length. This triangle is isosceles.

The two base angles are always opposite the congruent sides. One base angle is 25, so the other base angle must be 25 as well (base angles are congruent for isosceles triangles).

The three angles of this triangle are

25, 25 and 4x+2

Add those three angles up, set the result equal to 180, and solve for x

4x+2+25+25 = 180

4x+52 = 180

4x = 180-52

4x = 128

x = 128/4

Problem 7, part a)

We use the same idea as with the last problem above. This works because this triangle is also isosceles (due to the tickmarks).

The three angles of this triangle are

(4x+1), (4x+1) and (5x-4)

note how (4x+1) shows up twice because it is a base angle

Add up those angles and set it equal to 180 to solve for x

(4x+1) + (4x+1) + (5x-4) = 180

13x - 2 = 180

13x = 180+2

13x = 182

x = 182/13

x = 14

Using this x value, we can find angle F

angle F = 5x-4

angle F = 5*14-4

angle F = 70-4

Problem 7, part b)

We'll use the x value found back in part a) above.

angle D = 4x+1

angle D = 4*14+1

angle D = 56+1

Angle E is also 57, since D and E are congruent base angles

note how D+E+F = 57+57+66 = 180 to help confirm our answers

step-by-step explanation:

no of data

divide by no of mode

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: