A past survey of students taking a standardized test revealed that % of the students were planning on studying engineering in college. In a recent survey of students taking the SAT, % of the students were planning to study engineering. Construct a % confidence interval for the difference between proportions by using the following inequality. Assume the samples are random and independent. The confidence interval is __

Complete Question

The  complete question is shown on the first uploaded image  

The  95% confidence interval is  

Step-by-step explanation:

From the question we are told that

     The first sample  size  is  

     The first proportion  

     The second  sample size is  

     The  second  proportion is  

Given that the confidence level is  95%  then the level of significance is mathematically represented as

From the normal distribution table  we obtain the critical value of    the value is  

Now using the formula from the question to construct the 95% confidence interval we have  

Here

  =>  

 =>    

and  

 =>  

=>  

So  

21/58.

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30 miles

step-by-step explanation:

we know that 60 seconds equals 1 minute and 60 minutes 1 hour

44 ft       60 sec     60 min     158400   ft

  *   *   =

1 sec       1 min       1 hour         hour

we know that there are 5280 ft per mile

158400   ft       1 mile         30 miles

  *   =

1   hour               5280 ft     1 hour

so in 1 hour   it can travel 30 miles