Or the past 100 years, the average high temperature on october 1 is 78° with a standard deviation of 5°. what is the probability that the high temperature on october 1 of next year will be between 73° and 83°?

The probability is 0.683

Step-by-step explanation:

To calculate this, we shall be needing to calculate the z-scores of both temperatures

mathematically;

z-score = (x-mean)/SD

From the question mean = 78 and SD = 5

For 73

z-score = (73-78)/5 = -5/5 = -1

For 83

z-score = (83-78)/5 = 5/5 = 1

So the probability we want to calculate is within the following range of z-scores;

P(-1 <z <1 )

Mathematically, this is same as ;

P(z<1) - P(z<-1)

Using the normal distribution table;

P(-1<z<1) = 0.68269 which is approximately 0.683

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step-by-step explanation:

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the first option i believe

step-by-step explanation: