11. An AC waveform has a peak voltage of 50 VAC. What's the waveform's RMS voltage?
O A. 50.0 VAC
B. 35.4 VAC
C. 24.8 VAC
O D.52.8 VAC

Option B - 35.4 VAC

Step-by-step explanation:

Formula for peak voltage is;

V_p = V_rms × √2

Making V_rms the formula, we have;

V_rms = (V_p)/√2

We are given:Peak voltage: V_p = 50 VAC

Where 50 VAC means 50 Volts AC power

Thus;

V_rms = 50/√2

V_rms ≈ 35.4 VAC

So option B is correct

36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

hope this !

14.3

step-by-step explanation:

add all the numbers together.

9 + 12 + 15 + 16 + 17 + 17 = 86

now, divide 86 by how many numbers we have: 6.

86 / 6 = 14.3