The math club sells candy bars and drinks during football games. 60 candy bars and 110 drinks will sell for $265. 120 candy bars and 90 drinks will sell for $270. How much does each candy bar sell for?

$0.75 per candy bar

Step-by-step explanation:

For this problem, we simply need to set up a system of equations to find the value of a drink, and the value of a candy bar.

Let x represent the cost of a candy bar, and y represent the cost of a drink.

60x + 110y = 265

120x + 90y = 270

Now let's use the elimination method to solve for one of the variables:

60x + 110y = 265 --> -2 ( 60x + 110y = 265 ) --> -120x + -220y = -530

-120x + -220y = -530

120x + 90y = 270

-130y = -260

y = 2

Now plug the value of y into one of the equations to find the value for x:

60x + 110y = 265

60x + 110 (2) = 265

60x + 220 = 265

60x = 45

x = 45 / 60

x = 0.75

With this, we know that the cost of a candy bar is $0.75 and the cost of drink is $2.00.

Cheers.

c

step-by-step explanation:

because of the levels

2 is the final ! : )