A vertical pole is placed in the ground at a campsite outside Salt Lake City, Utah. One winter day, 16 of the pole is in the ground, 23 of the pole is covered in snow, and 1.8 ft is above the snow. How long is the pole, and how deep is the snow

Length of the pole = 10.8 ft

Depth of the snow = 7.2 ft

Step-by-step explanation:

The correct question is

A vertical pole is placed in the ground at a campsite outside Salt Lake City, Utah. One winter day, 1/6 of the pole is in the ground, 2/3 of the pole is covered in snow, and 1.8 ft is above the snow. How long is the pole, and how deep is the snow.

The fraction of the pole in the ground = 1/6

The fraction of the pole in the snow = 2/3

The length of the pole above the snow = 1.8 ft

Total fraction of the length of the pole = 1

For the fraction of the length above the snow, we solve as

1/6 + 2/3 + = 1

= 1 - 1/6 - 2/3 = 1/6

This means that the length of the pole above the snow 1.8 ft = 1/6 of the length of the pole.

Also, the fraction of the pole in the ground = 1/6

this means that the length of the pole in the ground = 1.8 ft

If 1/6 of the length of pole is 1.8 ft,

the length of the pole = 1.8 ft x 6 = 10.8 ft

Length of the pole in the snow = 2/3 of 10.8 = 2/3 x 10.8 = 7.2 ft

this means that the the snow is 7.2 ft deep

statement #3: proof- ang is congruent to ang ecd : angles are congruent.  

step-by-step explanation:

1: the missing angles in statement #3  

a.) acb  

reason- the reason why the answer is acb is because angle ecd and angle acb are both the same size *that's what the word congruent means this is really simple.  

2: the missing word in reason #3  

c.) vertical  

reason- the reason why the answer is vertical is because the angles in that diagram on figure 2 is slanted, which is vertical, and the e and a both lay on vertical lines. along with the other's, but e and a are the 2 main points you want to focus on. and c is kind of like your starting point, because c is for both angles, not just one.  

i hope that was and understanding.