Two hikers are 22 miles apart and walking toward each other. They meet in 5 hours. Find the rate of each hiker if one hiker walks 2.2 mph faster than the other

The hikers A and B travel at rates of 1.1 miles per hour and 3.3 miles per hour, respectively.

Step-by-step explanation:

Let suppose that each hiker travels at constant speed, such that kinematic formulas are, respectively:

Hiker A

Hiker B

Relationship

(They walk toward each other)

Where:

, - Initial and final position of the hiker A, measured in miles.

, - Initial and final position of the hiker B, measured in miles.

- Time, measured in hours.

, - Velocities of hikers A and B, measured in miles per hour.

Given that , , and , the system of equation is reduced to the following:

Now, the velocity of the hiker A is:

The hikers A and B travel at rates of 1.1 miles per hour and 3.3 miles per hour, respectively.

7. 153.86 ft

8. 12.56 ft

9. 78.5 m

10. 379.94 in

11. 132.665 m

12. 12.56 yd

13. 226.865 ft

14. 113.04 ft

15. 63.585 ft

16. 254.34 m

17. 50.24 cm

step-by-step explanation:

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trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral