Create an equation!
a graph has a y-intercept at -5, no x-intercepts, and discontinuous point...
Mathematics, 20.09.2019 12:30 gatornathan79
Create an equation!
a graph has a y-intercept at -5, no x-intercepts, and discontinuous points at (-1,-5) and (3, -5). i want to form an equation for this graph, but i don't know how the y-intercept relates to the graph of a rational function. here's all i have so far:
y = (x+1)(x-3)/(x+1)(x-3)
i realize this isn't even close to being complete; i need some direction on how to finish the equation. any would be appreciated.
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