What is the solution to the situation below? The sum of three consecutive integers is 42

13,14,15

Step-by-step explanation:

let the first number be n

The next 2 consecutive numbers will be

n+1 and n+2

Sum of these numbers is 42

n+ n+1+n+2=42

Combine like terms

3n+3=42

3n=42-3=39

n=39/3=13

So the numbers are

n=13

n+1=13+1=14

n+2=13+2=15