Could anyone help me with this? Thanks in advance x

find b: since the triangle is right angle triangle apply the Pythagorean theorem

c²+b²=d²

b²=d²-c²

b²=16²-12²

b²=256-144

b²=112

the sum of the angle of the triangle=180

( in top Δ abd ) sin Ф=opp/hyp

sinФ=b/d=4√7/16= √7/4  radian

convert to degrees : √7/4 *180/π= 37.91 almost 38 degrees

find a=?? apply law of cosine

a²= d^2 + c^2 − 2dc cosA

a²=16² + 12²-2(16)(12)cos38

a =√(16² + 12²-2(16)(12)cos38)

(i hope it is right )

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i