Please I need help, if you can

First building = 456

Second building = 438

Third building = 383

Step-by-step explanation:

First building = 73 + x

Second building = 55 + x

Third building = x

Total height of three buildings = 1277

(73 + x) + (55 + x) + (x) = 1277

73 + x + 55 + x + x = 1277

128 + x + x + x = 1277

128 + 3x = 1277

3x = 1149

x = 383

This is the height of the third building.

First building = 73 + x = 73 + 383 = 456

Second building = 55 + x = 55 + 383 = 438

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752