Planes X and Y and points J, K, L, M, and N are shown. Vertical plane X intersects horizontal plane Y. Point L is on the left half of plane Y. Point N is on the bottom half of plane X. Point M is on the right half of plane Y. Point K is on the top half of plane X. Point J is above and to the left of the planes. Exactly how many planes contain points J, K, and N? 0 1 2 3

step-by-step explanation:

i hate black

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

3100

step-by-step explanation: