Action video rents dvds and video games to its customers. The cost to rent d, DVD movies, is $3.50 each and the cost to rent r, video games, is $2.50 each. Which of these represents the possible number of DVDs that could be rented for no more that $20?

d = 5.71

Step-by-step explanation:

Let

Quantity of DVD movies = d

Quantity of Video games = r

Price of DVD movies = $3.50

Price of video games = $2.50

Total budget plan for DVD movies= $20

Which of these represents the possible number of DVDs that could be rented for no more that $20

Price of DVD movies × Quantity of DVD movies = $20

$3.50 × d = $20

3.50d = 20

Divide both sides by 3.50

d = 20/3.50

= 5.71

Approximately to the nearest whole number = 6

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb