Please I need help with both problems .( also show work plz)

4. x = 50

5. x = 5

Step-by-step explanation:

For question 4:

For question 5:

4) x= -50

5) x= 5

Step-by-step explanation:

Number 5

Simplifying

-3x + -2 = -17

Reorder the terms:

-2 + -3x = -17

Solving

-2 + -3x = -17

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.

-2 + 2 + -3x = -17 + 2

Combine like terms: -2 + 2 = 0

0 + -3x = -17 + 2

-3x = -17 + 2

Combine like terms: -17 + 2 = -15

-3x = -15

Divide each side by '-3'.

x = 5

Simplifying

x = 5

Number 4

x/5+7 = -3 // + 3

x/5+3+7 = 0

1/5*x+10 = 0 // - 10

1/5*x = -10 // : 1/5

x = -10/1/5

x = -50

x = -50

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

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