Sarita showed the steps to solving the equation. 5 (x minus 3) + 7 (x + 4) = 73 Steps Sarita’s Solution Sarita’s Verification 1 5 x minus 15 + 7 x + 28 = 73 5 (5 minus 3) + 7 (5 + 4) = 73. 5 (negative 2) + 7 (9) = 73. Negative 10 + 63 = 73. 53 not-equal-to 73. 2 (5 + 7) x + (negative 15 + 28) = 73 3 12 x + 13 = 73 4 12 x + 60 5 x = 5 When Sarita tried to verify her answer, she found it was wrong. Which explains her mistake? Sarita’s solution is correct. She made an error in her verification. Sarita was supposed to add the 5 and 7 in the first step. Sarita added +13 instead of Negative 13 in the fourth step. Sarita was supposed to use the division property of equality in the third step.

Will mark brainliest. when ∆rst is translated 4 units down, what are the apparent coordinates of t’?

What is the quotient? x+5/ 3x²+4x+5 © 3x2 – 11 + x + s 3x – 11 + 60 x + 5 o 3x2 - 11 - 50 x + 5 3x – 11 - - x + 5

In new york city at the spring equinox there are 12 hours 8 minutes of daylight. the longest and shortest days of the year very by two hours and 53 minutes from the equinox in this year the equinox falls on march 21 in this task you use trigonometric function to model the hours of daylight hours on certain days of the year in new york city a.what is the independent and dependent variables? b.find the amplitude and the period of the function. c.create a trigonometric function that describes the hours of sunlight for each day of the year. d. graph the function you build in part c. e. use the function you build in part c to find out how many fewer daylight hours february 10 will have than march 21. you may look at the calendar.