A rectangle has a width, w and a length that is 3 more than 2 times longer than the width. Part a) Write an expression for the perimeter of the rectangle. Part b) Write an expression for the area of the rectangle.

Let's write down everything we know: L = 2 + 3W (length is 2 feet more than 3 times the width) A is 16 sq ft A = L x W If we substitute in the area formula so we only have one variable, W: L x W = 16 (2+3W) x W = 16 Multiplying out the paren 2W + 3W^2 = 16 Let's rearrange the terms: 3W^2 + 2W = 16 Subtracting 16 from each side: 3W^2 + 2W - 16 = 0