A bag of tulip bulbs contains red tulip bulbs, yellow tulip bulbs, and purple tulip bulbs. Suppose two tulip bulbs are randomly selected without replacement from the bag. (a) What is the probability that the two randomly selected tulip bulbs are both red? (b) What is the probability that the first bulb selected is red and the second yellow? (c) What is the probability that the first bulb selected is yellow and the second red? (d) What is the probability that one bulb is red and the other yellow?

This question is incomplete

Complete Question

A bag of 27 tulip bulbs contains 11 red tulip bulbs, 9 yellow tulip bulbs, and 7 purple tulip bulbs. Suppose two tulip bulbs are randomly selected without replacement from the bag. (a) What is the probability that the two randomly selected tulip bulbs are both red? (b) What is the probability that the first bulb selected is red and the second yellow? (c) What is the probability that the first bulb selected is yellow and the second red? (d) What is the probability that one bulb is red and the other yellow?

(a) 55/351

(b) 11/78

(c) 11/78

(d)529/702

Step-by-step explanation:

Total number of tulips = 27

Red tulip bulbs = 11

Yellow tulip bulbs = 9

Purple tulip bulbs = 7

Note that this probability is without replacement

(a) What is the probability that the two randomly selected tulip bulbs are both red?

Probability (that both are red)

= 11/27 × 10/26

= 55/351

(b) What is the probability that the first bulb selected is red and the second yellow?

Probability (that the first is red and the second is yellow)

= 11/27 × 9/26

= 99/702

= 11/78

(c) What is the probability that the first bulb selected is yellow and the second red?

Probability (that the first bulb selected is yellow and the second red)

9/27 × 11/26

= 99/702

= 11/78

(d) What is the probability that one bulb is red and the other yellow?

= Probability( that one bulb is red and the other yellow)

= 11/27 + 9/26

= (26 × 11) +(27 × 9)/702

= 529/702

the answer is d. 75%

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