I. The airport branch of a car rental company maintains a fleet of 50 SUVs. The interarrival time between requests for an SUV is 2.4 hours, on average, with a standard deviation of 2.4 hours. There is no indication of a systematic arrival patterns over the course of a day. Assume that, if all SUVs are rented, customers are willing to wait until there is an SUV available. An SUV is rented, on average, for 3 days, with a standard deviation of 1 day. a) What is the average number of SUVs parked in the company's lot

20

Step-by-step explanation:

Given that:

Number of SUVs maintained, m = 50

The interarrival time for an SUV "a" = 2.4 hours

The standard deviation  = 2.4 hours

Activity time p = 3 days = (24 × 3) hours = 72 hours

Standard deviation of activity time = 1 day = 24 hours

The objective is to calculate the average number of SUVs parked in the company's lot from above.

To determine that, we need to first find the utilization rate "u" by using the formula:

Utilization

u = 0.6

u = 60%

Thus, the average number of SUVs parked in the lot can be estimated as:

The average number of SUVs = 50 - (60% × 50)

The average number of SUVs = 50 - 30

The average number of SUVs= 20

Thus, the avg. number of SUVs parked in the company's lot = 20

b

step-by-step explanation:

given

- 2 (3x + 12y - 5 - 17x - 16y + 4 )

simplify the parenthesis by collecting like terms

= - 2 (- 14x - 4y - 1) ← distribute the parenthesis by - 2

= 28x + 8y + 2 → b

all but the second one

step-by-step explanation:

cuz that one goes over 180

mark brainliest