The width of a rectangle card is 2cm less than the length and the area is 35cm²

The width of a rectangle card is 2cm less than the length and the area of rectangle is 35cm²

We have to find length and breadth of rectangle.

Let length of the rectangle be x cm.

Given that, width is 2cm less than the length.

∴ Width = (x - 2) cm

➤ Area of rectangle :

⭆ Area of rectangle = 35

⭆ length × width = 35

⭆ x × (x - 2) = 35

⭆ x² - 2x - 35 = 0

⭆ x² - 7x + 5x - 35 = 0

⭆ x(x - 7) + 5(x - 7) = 0

⭆ x = 7 or x = -5

We know that, length can't be negative.

∴ Length of rectangle = 7cm

∴ Width of rectangle = 5cm

this question relies purely on our observation of the graph and a knowledge of the behaviour of a graph of a hyperbola.

now, what we should realise is that there are two asymptotes - one at x = 0 and one at y = 0. what this means is that the graph will gradually approach, but never touch, these two lines. so, as x becomes more positive (ie. 'a very large positive number'), it will get closer to the line y = 0 (ie. the x-axis) - which means that the value of f(x) will gradually become smaller and closer to 0 - but will never reach it.

we can also observe this from the right half of the graph, where the graph gradually lowers closer and closer to the x-axis as x increases. what is important to note however is that it will never actually touch the x-axis (ie. f(x) will not equal 0) since there is an asymptote there. given this, we can see that option d, f(x) is a very small positive number, would be correct.

im not sure

step-by-step explanation: