−14a−(−48a)
mind helping

\mathrm{Simplify}\:\frac{\left(2ab^3\right)^{-1}}{20\cdot \left(2^{-1}\cdot \:ba^5\right)^2}\cdot \left(\frac{4ab^{-1}}{5b}\right)^{-2}:\quad \frac{5}{32a^{13}b}

Step-by-step explanation:

\mathrm{Simplify}\:\frac{\left(2ab^3\right)^{-1}}{20\cdot \left(2^{-1}\cdot \:ba^5\right)^2}\cdot \left(\frac{4ab^{-1}}{5b}\right)^{-2}:\quad \frac{5}{32a^{13}b}

associative property hopes this ! : )

step-by-step explanation:

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step-by-step explanation:

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