Triangle ABC with vertices A (-1, 4), B( -4, 1), and C(-1, 1) is reflected across the y-axis and then translated 4 units to the left to form triangle A’B’C’. What are the coordinates of the vertices of triangle A’B’C’? A
A’ (1, 4), B’ (4, 1), C’ (1, 1)
B
A’ (-3, 4), B’ (0, 1), C’ (-3, 1)
C
A’ (-1, -4), B’ (-4, -1), C’ (-1, -1)
D
A’ (-5, -4), B’ (-8, -1), C’ (-5, -1)

Given:

Triangle ABC with vertices A (-1, 4), B( -4, 1), and C(-1, 1) is reflected across the y-axis and then translated 4 units to the left to form triangle A’B’C’.

To find:

The coordinates of the vertices of triangle A’B’C’.

Solution:

If triangle ABC reflected across y-axis, then

Coordinates of image after reflection across y-axis are

Then triangle translated 4 units to the left to form triangle A’B’C’.

Therefore, the vertices of triangle A’B’C’ are A’ (-3, 4), B’ (0, 1), C’ (-3, 1).

Hence, the correct option is B.

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

my dear correct answer is option number 3