If m∠SQP = 34°, find m∠SQR
RQP=5x
SQR=3x-2

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!

table a is wierd

step-by-step explanation:

6*f

step-by-step explanation: hi!