A spring exerts a force of 1000 pounds when stretched five feet from its equilibrium position. How much work is needed to stretch the spring six feet from its equilibrium position?

1000 pounds / 5 feet = 200 pounds per foot.

200 pounds per foot x 6 feet = 1200 pounds.

The answer is 1,200 pounds.

7. 153.86 ft

8. 12.56 ft

9. 78.5 m

10. 379.94 in

11. 132.665 m

12. 12.56 yd

13. 226.865 ft

14. 113.04 ft

15. 63.585 ft

16. 254.34 m

17. 50.24 cm

step-by-step explanation:

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im pretty sure it would be 5 am, hope that , and give brainliest and guys if this is right then press the button and give 5 stars