Farmer Jane has many hens that have laid many eggs. Before the eggs hatch, Jane wants to count how many eggs are blue, how many are brown, and how many are white.
Jane counts that, of all the eggs, 6 are blue and 25% are brown.
If 10% of the eggs are blue, how many of the eggs are white?
a) 15
b) 21
c) 39
d) 65

The correct option is;

c) 39

Step-by-step explanation:

The given information are;

The number of eggs that are blue = 6

The percentage of eggs that are brown = 25%

The percentage of eggs that are blue = 10%

Let the number of eggs Jane has = X

Therefore;

10% of X = 10/100 × X = 6

X = 6 × 100/10 = 60

The number of eggs Jane has = X = 60

The percentage of the eggs that are white eggs = 100 - (The percentage of eggs that are brown + The percentage of eggs that are blue)

The percentage of the eggs that are white eggs = 100 - (10 + 25) = 65%

The percentage of the eggs that are white eggs = 65%

∴ The number of  eggs that are white = 65% of X = 65/100 × X= 65/100× 60 = 39 eggs

The number of  eggs that are white = 39 eggs.

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation:

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step-by-step explanation:

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