Whats the distance between (1,2) and (4,-2)

5 units

Step-by-step explanation:

Distance formula:

Square root of those quantities. x2 and x1 mean the x values from one coordinate and the other, and the same goes for the y-coordinates. So y2-y1 represents (-2) - (2) and x2-x1 = (4) - (1). The answers you get (-4 and 3, respectively), now have to be squared, then added together. So (-4)^2 = 16 and (3)^2 = 9. Add 16 and 9 together you get 25. Final answer, you square root 25 and you get 5. Technically the square root of 25 is both positive and negative 5, but you cannot get a negative number for distance in this case (vectors are different).

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !