Write the slope-intercept form of the equation of the line described. Through (-2, -1) and parallel to y=-2x-1

y= -2x -5

Step-by-step explanation:

Slope-intercept form:

y= mx +c, where m is the slope and c is the y-intercept.

Parallel lines have the same slope.

Thus, to find the value of the slope of the line, we have to find the slope of the given line.

y= -2x -1

Since the coefficient of x is -2 and the equation is already in slope-intercept form, the slope of the given line is -2.

Substitute m= -2 into the equation:

y= -2x +c

To find the value of c, substitute a pair of coordinates.

When x= -2, y= -1,

-1= -2(-2) +c

-1= 4 +c

c= -1 -4 (-4 on both sides)

c= -5

Thus, the equation of the line is y= -2x -5.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.