What is the probability that six consecutive integers will be chosen as the winning numbers in a lottery where each number chosen is an integer between 1 and 40 (inclusive)?

0.00000911843

Step-by-step explanation:

Since the number chosen is an integer between 1 and 40 (inclusive), it means that the number of terms is 40.

Thus; n = 40

Probability that 6 integers (r = 6) which is number of possible outcomes will be gotten without repetition is gotten by the combination formula which is;

C(n, r) = n!/(r!(n - r)!)

C(40, 6) = 40!/(6!(40 - 6)!)

C(40,6) = 3838380

Now, to select 6 consecutive integers, it can be done in different combinations such as;

(1 - 6, 2 - 7, 8 - 13,...e.t.c)

Total number of favorable outcomes will be 35.

Now,probability that six consecutive integers will be chosen as the winning numbers is;

P(that six consecutive integers will be chosen as the winning numbers) = number of favorable outcomes/number of possible outcomes = 35/3838380 = 0.00000911843

15%

step-by-step explanation:

use the table and count the number of guesses that has two correct answers.

the following are two correct answers

10010, 01100, 11000

a total of 3 numbers having 2 correct guesses out of 20 questions.

probability of getting 2 correct guesses = the number of questions getting 2 correct answers / total number of questions.

= 3/20

to convert it into percent multiply by 100, we get

= 3/20 * 100

= 15%

the answer is 15%

you.

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