What are the possible numbers of positive real, negative real, and complex zeros of f(x) = 8x4 + 13x3 − 11x2 + x + 9? (2 points) Group of answer choices

Positive Real: 1
Negative Real: 3 or 1
Complex: 2 or 0

Positive Real: 2 or 0
Negative Real: 0
Complex: 2 or 4

Positive Real: 3 or 1
Negative Real: 1
Complex: 2 or 0

Positive Real: 2 or 0
Negative Real: 2 or 0
Complex: 4, 2 or 0

666666666666666666666

6

6

6

6

6

6

6

66

6

6

6

66

6

66answer:

step-by-step explanation:

answer:   c ?

step-by-step explanation:

i'm sorry mate, but i am not seeing any figures. i am unable to solve this for you.

asnwer is (g o h o f)(x) = 2x - 6/x + 7

step-by-step explanation:

given,

f(x) = x - 3/x

g(x) = x + 3

h(x) = 2x + 1

we need to find : (g o h o f)(x)

we can write (g o h o f)(x) = g[ h{ f(x) } ]

so first we find h{f(x)}

h{f(x)} = f(x) + 3 = (x - 3/x) + 3

h{f(x)} = x - 3/x + 3

now we find g[ h{ f(x) } ].

g[ h{ f(x) } ] = g(x - 3/x + 3)       {plug h{f(x)} = x - 3/x + 3 in g[h{f(x)}] }

g(x - 3/x + 3) = 2 (x - 3/x + 3) + 1

                    = 2x - 6/x + 6 + 1

                    = 2x - 6/x + 7

hence we get (g o h o f)(x) = 2x - 6/x + 7