In △ACD, if AC≅AD, m∠A = 3x − 4, m∠C = 5x + 1, and m∠D = 7x − 27, find x and the measure of each angle.

x = 14

m∠A = 38°

m∠C = 71°

m∠D = 71°

Step-by-step explanation:

By the property of a triangle,

"Sum of interior angles of a triangle is 180°"

m∠A + m∠C + m∠D = 180°

By substituting the values of the angles given in the question,

(3x - 4)° + (5x + 1)° + (7x - 27)° = 180°

(3x + 5x + 7x) + (-4 + 1 - 27) = 180

15x - 30 = 180

15x = 210

x = 14

Therefore, m∠A = 3x - 4

                           = 3(14) - 4

                           = 38°

m∠C = 5x + 1

        = 5(14) + 1

        = 71°

m∠D = 7x - 27

         = 7(14) - 27

         = 98 - 27

         = 71°

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