A line passes through the point (4, –6) and has a slope of Negative three-fourths. Which is the equation of the line? y = negative three-fourths x minus 3
y = negative three-fourths x minus 6
y = negative 3 x minus three-fourths
y = negative 6 x minus three-fourths

Option A

Step-by-step explanation:

The equation of line is

Solution:

Given that line passes through the point (4, –6) and has a slope of Negative three-fourths

Given point is (x, y) = (4, -6)

The equation of line passing through point (x, y) and slope "m" is given as:

y = mx + c eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Substitute (x, y) = (4, -6) and  in eqn 1

The required equation of line is given as:

Thus the equation of line is found

sorry not sure

step-by-step explanation:

a

step-by-step explanation:

the denominator cannot be the same as one of the factors.

8 denominator times 2 denominator = 16

and 7 numerator time 11 = 77

77/16= 77/16 ( they cannot be further simplified)