Determine the zeros of f(x) when n=2. Please help I attached the image

x=0 and -2

Notice a n=8, g(n)=0 and f(x) = 0.  If n<8, the coefficients for f(x) become negative and when n>8, the coefficients becomes positive.  It won't affect x=0 because x can be factor out and be equal to zero but will affect the second zero

Step-by-step explanation:

Given:  g(n) = 1/2*n - 4 and f(x)= g(n)x^2 + 2(g(n))x; n≠8

n = 2

g(n) = 1/2*n - 4

g(n) = 1/2*2 - 4 = 1-4 = -3

f(x)= g(n)x^2 + 2(g(n))x

f(x)= -3x^2 + 2(-3)x = -3x^2 - 6x

0=  -3x^2 - 6x; factor out -3x

0 = -3x(x + 2)

-3x = 0; x=0

(x+2)= 0; x=-2

Notice a n=8, g(n)=0 and n<8, the coefficients for f(x) become negative and when n>8, the coefficients becomes positive

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !