DEPERATE PLZ HELP IM ON A TIMED TEST write the slope intercept form of the line that passes through the two points given (-1,-8) (2,10)

y = 6x - 2

Step-by-step explanation:

Let the equation of the line be y = mx + c

m = (10 - (-8))/(2 - (-1)) = 6

sub (2, 10):

10 = 6(2) + c

c = -2

therefore, the equation of the line is y = 6x - 2

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option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

16 is the absolute value

step-by-step explanation: