Anyone out there doing Friday school one this sucks two can any one help me
17 points and brainliest when the opportunity comes

In a word processing document or on a separate piece of paper, use the guide to construct a two column proof proving DC || AB, given AB = CD and AD = CB. Upload the entire proof below.

Given:

segment AB = segment CD

segment AD = segment CB

Prove:

segment DC || segment AB

STATEMENT REASON
1. 1.
2. AC = AC 2.
3. 3. SSS (Side-Side-Side)
4angle .1 = angle 4 4.
5. 5.

1.As BC = EF is a given statement in the question

2.AB + BC = AC because the definition of betweenness gives us a clear idea that if a point B is between points A and C, then the length of AB and the length of BC is equal to the length of AC. Also according to Segment addition postulate, AB + BC = AC. For example, if AB = 5 and BC= 7 then AC = AB + BC → AC = 12

3.AC > BC because the Parts Theorem (Segments) mentions that if B is a point on AC between A and C, then AC > BC and AC>AB. So, if we observe the question figure, we can realize that point B lies on the segment AC between points A and C.

4. AC > EF because BC is equal to EF and if AC>BC, then it must be true that the length of AC must greater than the length segment EF.

STATEMENT                              REASON  

1. BC = EF                                    1. Given

2. AB + BC = AC                         2. Betweenness

3. AC > BC                                   3. Def. of segment inequality

4. AC > EF                                   4. Def. of congruent segments

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

read more on -

1010: 3030

is it i think